8x^2-39x-200=0

Solution for 8x^2-39x-200=0 equation:

8x^2-39x-200=0

a = 8; b = -39; c = -200;
Δ = b2-4ac
Δ = -392-4·8·(-200)
Δ = 7921
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{7921}=89$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-39)-89}{2*8}=\frac{-50}{16}
=-3+1/8
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-39)+89}{2*8}=\frac{128}{16}
=8
$